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js实现图片旋转的三种方法

作者:佚名    责任编辑:admin    更新时间:2022-06-22

 这篇文章主要介绍了js实现图片旋转的三种方法,需要的朋友可以参考下

1 使用jQueryRotate.js实现    示例代码:  代码如下: <!DOCTYPE html>  <html>  <head>  <title></title>  <style type="text/css">  #div1 {  width: 800px;  height: 600px;  background-color: #ff0;  position: absolute;  }  .imgRotate {  width: 100px;  height: 80px;  position: absolute;  top: 50%;  left: 50%;  margin: -40px 0 0 -50px;  }  </style>  </head>  <body>  <div id="div1">  <img id="img1" class="imgRotate" src="http://www.baidu.com/img/logo-yy.gif" />  <input id="input2" type="button" value="btn2"></input>  </div>  </body>  <script type="text/javascript" src="jquery.min.js"></script>  <script type="text/javascript" src="jQueryRotate.js"></script>  <script type="text/javascript">  var num = 0;  $("#input2").click(function(){  num ++;  $("#img1").rotate(90*num);  });  </script>  </html>    测试结果:chrome下效果正常,旋转后img对象仍为img对象;ie8下效果正常,但旋转后img对象变为下面对象,由于对象变化,若旋转后仍按原来方法获取img对象,则会报js错误。欲获取image对象,可根据class获取。如果图像旋转后,不进行其它操作,则可用此方法。若进行其它操作,如放大、缩小图像,则此方法实现较复杂。   代码如下: <span ...>  <rvml:group class="rvml"...>  <rvml:image class="rvml".../>  </rvml:group>  </span>    2 使用Microsoft提供的Matrix对象    示例代码:   代码如下: <!DOCTYPE html>  <html>  <head>  <title></title>  <style type="text/css">  #div1 {  width: 800px;  height: 600px;  background-color: #ff0;  position: absolute;  }  .imgRotate {  width: 100px;  height: 100px;  position: absolute;  top: 50%;  left: 50%;  margin: -50px 0 0 -50px;  }  #imgRotate {  width: 100px;  height: 100px;  position: absolute;  top: 50%;  left: 50%;  margin: -50px 0 0 -50px;  }  </style>  </head>  <body>  <div id="div1">  <img id="img1" class="imgRotate" src="http://www.baidu.com/img/logo-yy.gif" />  <input id="input1" type="button" value="btn1"></input>  </div>  </body>  <script type="text/javascript" src="jquery.min.js"></script>  <script type="text/javascript">  function rotate(id,angle,whence) {  var p = document.getElementById(id);    // we store the angle inside the image tag for persistence  if (!whence) {  p.angle = ((p.angle==undefined?0:p.angle) + angle) % 360;  } else {  p.angle = angle;  }    if (p.angle >= 0) {  var rotation = Math.PI * p.angle / 180;  } else {  var rotation = Math.PI * (360+p.angle) / 180;  }  var costheta = Math.cos(rotation);  var sintheta = Math.sin(rotation);    if (document.all && !window.opera) {  var canvas = document.createElement('img');    canvas.src = p.src;  canvas.height = p.height;  canvas.width = p.width;    canvas.style.filter = "progid:DXImageTransform.Microsoft.Matrix(M11="+costheta+",M12="+(-sintheta)+",M21="+sintheta+",M22="+costheta+",SizingMethod='auto expand')";  } else {  var canvas = document.createElement('canvas');  if (!p.oImage) {  canvas.oImage = new Image();  canvas.oImage.src = p.src;  } else {  canvas.oImage = p.oImage;  }    canvas.style.width = canvas.width = Math.abs(costheta*canvas.oImage.width) + Math.abs(sintheta*canvas.oImage.height);  canvas.style.height = canvas.height = Math.abs(costheta*canvas.oImage.height) + Math.abs(sintheta*canvas.oImage.width);    var context = canvas.getContext('2d');  context.save();  if (rotation <= Math.PI/2) {  context.translate(sintheta*canvas.oImage.height,0);  } else if (rotation <= Math.PI) {  context.translate(canvas.width,-costheta*canvas.oImage.height);  } else if (rotation <= 1.5*Math.PI) {  context.translate(-costheta*canvas.oImage.width,canvas.height);  } else {  context.translate(0,-sintheta*canvas.oImage.width);  }  context.rotate(rotation);  context.drawImage(canvas.oImage, 0, 0, canvas.oImage.width, canvas.oImage.height);  context.restore();  }  canvas.id = p.id;  canvas.angle = p.angle;  p.parentNode.replaceChild(canvas, p);  }    function rotateRight(id,angle) {  rotate(id,angle==undefined?90:angle);  }    function rotateLeft(id,angle) {  rotate(id,angle==undefined?-90:-angle);  }  $("#input1").click(function(){  $("img.imgRotate").attr("id","imgRotate");  rotateLeft("imgRotate",90);  $("#imgRotate").attr("top","50%");  $("#imgRotate").attr("left","50%");  $("#imgRotate").attr("margin","-50px 0 0 -50px");  });  </script>  </html>    测试结果:chrome下效果正常,但旋转后img对象变为canvas对象;ie8下效果正常,旋转后img对象仍为img对象。Matrix()参数较多,使用时需较多计算。    3 使用Microsoft提供的BasicImage对象    示例代码:  代码如下: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">  <html xmlns="http://www.w3.org/1999/xhtml">  <head>  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />  </head>  <body>  <img id="image" src="http://www.baidu.com/img/logo-yy.gif" />  <input id="input2" type="button" value="btn2"></input>  </body>  <script type="text/javascript" src="jquery.min.js"></script>    <script type="text/javascript">  var num = 0;  $("#input2").click(function(){  num = (num + 1) % 4;  document.getElementById('image').style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation='+num+')';  });  </script>  </html>    测试结果:chrome下不能旋转;ie8下效果正常,旋转后img对象仍为img对象。BasicImage()仅一个参数。    查看这三种方法的代码会发现,本质上是一种解决方案:chrome下使用canvas对象实现,ie8下使用VML或者Matrix()或BasicImage()实现。本人近期改造一个组件:其中涉及到旋转、放大图片,由于jQueryRotate.js在ie8下会生成一个新的对象,导致放大图片前选择图片时,需要进行特殊处理。后决定对chrome、ie8分开处理,chrome下使用jQueryRotate实现,ie8下使用BasicImage()实现,保证了代码的简洁性和可读性。